Electromagnetics 1 mark Plane waves Numerical answer

Average power density of a plane wave in free space

BlinkNBuild practice problem · GATE standard, authored and verified in-house

A uniform plane wave propagates in free space with a peak electric field amplitude of $E_0 = 10\ \text{V/m}$. Take the intrinsic impedance of free space as $\eta_0 = 377\ \Omega$.

The time-average power density, in W/m$^2$, is ________.

Show the step-by-step derivation
Answer 0.1326 W/m$^2$ (accept 0.13 to 0.135) W/m$^2$ (accept 0.13 to 0.135)

Step-by-step derivation

  1. For a uniform plane wave in a lossless medium, $\vec{E}$ and $\vec{H}$ are in phase and perpendicular, related by the intrinsic impedance: $$H_0 = \frac{E_0}{\eta_0}.$$
  2. The time-average Poynting vector magnitude is $$S_{avg} = \tfrac{1}{2}\,E_0 H_0 = \frac{E_0^2}{2\eta_0},$$ where the factor of $\tfrac{1}{2}$ comes from averaging $\cos^2$ over a cycle.
  3. Substitute the given values: $$S_{avg} = \frac{10^2}{2 \times 377} = \frac{100}{754}.$$
  4. Evaluate: $$S_{avg} = \mathbf{0.1326\ W/m^2}.$$
  5. Cross-check via RMS. The RMS field is $E_{rms} = 10/\sqrt{2} = 7.071$ V/m, and $E_{rms}^2/\eta_0 = 50/377 = 0.1326$ W/m$^2$. Same answer - the $\tfrac{1}{2}$ and the $\sqrt{2}$ are the same fact stated twice. ✓
The trap this question is built around Omitting the factor of $\tfrac{1}{2}$ and answering $0.265$ W/m$^2$. That is the peak power density, not the average. If the field is given as RMS, the half disappears - so always check which the question specifies.

The idea behind this question

The Poynting vector gives the power flowing per unit area in an electromagnetic wave. For a sinusoidal plane wave with peak electric field $E_0$ in a medium of intrinsic impedance $\eta$, the time-average power density is $E_0^2/(2\eta)$ - the same form as the power $V^2/2R$ from a sinusoidal voltage of peak $V$.

Try a variation

What is the average power density for $E_0 = 20$ V/m in free space?

Show the answer

Answer: $0.5305$ W/m$^2$

$20^2 / (2 \times 377) = 0.5305$ W/m$^2$.

Other mistakes to avoid

  • Using the magnetic field amplitude with the electric-field formula.
  • Using the free-space impedance when the wave travels in a dielectric.

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